Solve for 'θ': cot2(θ - 5)° = 3

Solve for 'θ': cot²(θ - 5)° = 3

योग

cot²(θ - 5)° = 3
⇒ cot(θ - 5)° = `sqrt(3)`
⇒ cot(θ - 5)° = cot 30°
⇒ (θ - 5)° = 30°
⇒ θ = 30°+ 5°
⇒ θ = 35°.

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Trigonometric Equation Problem and Solution

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अध्याय 22: Trigonometrical Ratios of Standard Angles - Exercise 27.1

अध्याय 22 Trigonometrical Ratios of Standard Angles
Exercise 27.1 | Q 7.2

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