Advertisements
Advertisements
प्रश्न
Evaluate the following: `(3sin^2 40°)/(4cos^2 50°) - ("cosec"^2 28°)/(4sec^2 62°) + (cos10° cos25° cos45° "cosec"80°)/(2sin15° sin25° sin45° sin65° sec75°)`
Advertisements
उत्तर
`(3sin^2 40°)/(4cos^2 50°) - ("cosec"^2 28°)/(4sec^2 62°) + (cos10° cos25° cos45° "cosec"80°)/(2sin15° sin25° sin45° sin65° sec75°)`
= `(3sin^2 (90° - 50°))/(4cos^2 50°) - ("cosec"^2 (90° - 62°))/(4sec^2 62°) + (cos(90° - 80°) cos25° xx 1/sqrt(2) xx 1/(sin80°))/(2sin(90° - 75°) xx 1/sqrt(2) xx sin(90° - 25°) xx 1/(cos75°))`
= `(3cos^2 50°)/(4cos^2 50°) - (sec^2 62°)/(4sec^2 62°) + (sin80° xx cos25° xx 1/(cos75°))/(2cos75° xx cos25° xx 1/(cos75°))`
= `(3)/(4) - (1)/(4) + (1)/(2)`
= `(1)/(2) + (1)/(2)`
= 1.
APPEARS IN
संबंधित प्रश्न
If 4 sin2 θ – 1 = 0 and angle θ is less than 90°, find the value of θ and hence the value of cos2 θ + tan2 θ.
Solve the following equation for A, if sec 2A = 2
If sin 3A = 1 and 0 < A < 90°, find cos 2A
Find the value of 'A', if 2 cos A = 1
If θ = 30°, verify that: 1 - sin 2θ = (sinθ - cosθ)2
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos2 (30° + θ) + sin2 (45° - θ)
Find the value of 'x' in each of the following:
Find x and y, in each of the following figure:
Evaluate the following: tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ)
If tan4θ = cot(θ + 20°), find the value of θ if 4θ is an acute angle.
