Find the value 'x', if:

बेरीज

BEDC is a rectangle.
⇒ BE
= DC
= `60sqrt(3)"m"`
In right ΔAEB,

tan30° = `"AE"/"BE"`

⇒ `(1)/sqrt(3) = "AE"/(60sqrt(3)`
⇒ AE = 60m
Now,
x = AD = AE + ED
= 60 + 15
= 75m.

shaalaa.com

Trigonometric Equation Problem and Solution

या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

पाठ 27: Trigonometrical Ratios of Standard Angles - Exercise 27.2

पाठ 27 Trigonometrical Ratios of Standard Angles
Exercise 27.2 | Q 9.6

In ΔABC, ∠B = 90° , AB = y units, BC = `(sqrt3)` units, AC = 2 units and angle A = x°, find:

Find the magnitude of angle A, if 2 cos² A - 3 cos A + 1 = 0

Find the value of 'A', if (2 - cosec 2A) cos 3A = 0

If sin α + cosβ = 1 and α= 90°, find the value of 'β'.

If `sqrt(2) = 1.414 and sqrt(3) = 1.732`, find the value of the following correct to two decimal places tan60°

If A = 30°, verify that cos2θ = `(1 - tan^2 θ)/(1 + tan^2 θ)` = cos⁴θ - sin⁴θ = 2cos²θ - 1 - 2sin²θ

Find the value of 'x' in each of the following:

Evaluate the following: `(sin25° cos43°)/(sin47° cos 65°)`

Evaluate the following: `(tan42°)/(cot48°) + (cos33°)/(sin57°)`

Evaluate the following: `(sin0° sin35° sin55° sin75°)/(cos22° cos64° cos58° cos90°)`