Advertisements
Advertisements
प्रश्न
Find the value 'x', if:
Advertisements
उत्तर
BEDC is a rectangle.
⇒ BE
= DC
= `60sqrt(3)"m"`
In right ΔAEB,
tan30° = `"AE"/"BE"`
⇒ `(1)/sqrt(3) = "AE"/(60sqrt(3)`
⇒ AE = 60m
Now,
x = AD = AE + ED
= 60 + 15
= 75m.
APPEARS IN
संबंधित प्रश्न
If 4 cos2 x = 3 and x is an acute angle;
find the value of :
(i) x
(ii) cos2 x + cot2 x
(iii) cos 3x (iv) sin 2x
Solve for x : cos `(x/(2)+10°) = (sqrt3)/(2)`
If sin α + cosβ = 1 and α= 90°, find the value of 'β'.
Solve for 'θ': cot2(θ - 5)° = 3
If θ = 30°, verify that: sin 3θ = 4sinθ . sin(60° - θ) sin(60° + θ)
If θ < 90°, find the value of: sin2θ + cos2θ
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos2 (30° + θ) + sin2 (45° - θ)
Evaluate the following: sin31° - cos59°
Evaluate the following: sin28° sec62° + tan49° tan41°
Evaluate the following: `(tan42°)/(cot48°) + (cos33°)/(sin57°)`
