Evaluate the following: tan 42 ° cot 48 ° + cos 33 ° sin 57 °

Evaluate the following: `(tan42°)/(cot48°) + (cos33°)/(sin57°)`

बेरीज

`(tan42°)/(cot48°) + (cos33°)/(sin57°)`

= `(tan(90° - 48°))/(cot48°) - (cos(90° - 57°))/(sin57°)`

= `(cot48°)/(cot48°) - (sin57°)/(sin57°)`

= 1 - 1
= 0.

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Trigonometric Equation Problem and Solution

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पाठ 27: Trigonometrical Ratios of Standard Angles - Exercise 27.3

पाठ 27 Trigonometrical Ratios of Standard Angles
Exercise 27.3 | Q 3.2

Calculate the value of A, if (sin A - 1) (2 cos A - 1) = 0

Solve for x : 2 cos 3x - 1 = 0

If 2 cos (A + B) = 2 sin (A - B) = 1;
find the values of A and B.

If A = 30°, verify that cos2θ = `(1 - tan^2 θ)/(1 + tan^2 θ)` = cos⁴θ - sin⁴θ = 2cos²θ - 1 - 2sin²θ

If θ < 90°, find the value of: sin²θ + cos²θ

If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of

cos² (30° + θ) + sin² (45° - θ)

Find lengths of diagonals AC and BD. Given AB = 24 cm and ∠BAD = 60°.

Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.

Evaluate the following: `(sec34°)/("cosec"56°)`

If A + B = 90°, prove that `(tan"A" tan"B" + tan"A" cot"B")/(sin"A" sec"B") - (sin^2"B")/(cos^2"A")` = tan²A