Advertisements
Advertisements
Question
Find the value 'x', if:
Advertisements
Solution

BEDC is a rectangle.
⇒ BE
= DC
= `60sqrt(3)"m"`
In right ΔAEB,
tan30° = `"AE"/"BE"`
⇒ `(1)/sqrt(3) = "AE"/(60sqrt(3)`
⇒ AE = 60m
Now,
x = AD = AE + ED
= 60 + 15
= 75m.
APPEARS IN
RELATED QUESTIONS
Solve for x : 2 cos 3x - 1 = 0
Calculate the value of A, if (sec 2A - 1) (cosec 3A - 1) = 0
Find the magnitude of angle A, if 2 cos2 A - 3 cos A + 1 = 0
If sin α + cosβ = 1 and α= 90°, find the value of 'β'.
Solve for 'θ': `sin θ/(3)` = 1
If θ = 30°, verify that: tan2θ = `(2tanθ)/(1 - tan^2θ)`
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
a. AB is `sqrt(3)` times of BC.
B. BC is `sqrt(3)` times of BC.
Evaluate the following: sec16° tan28° - cot62° cosec74°
Evaluate the following: `(sin36°)/(cos54°) + (sec31°)/("cosec"59°)`
If cos3θ = sin(θ - 34°), find the value of θ if 3θ is an acute angle.
