Advertisements
Advertisements
Question
Solve for 'θ': `sin θ/(3)` = 1
Advertisements
Solution
`sin θ/(3)` = 1
⇒ `sin θ/(3)` = sin 90°
⇒ `θ/(3)` = 90°
⇒ θ = 270°.
APPEARS IN
RELATED QUESTIONS
State for any acute angle θ whether sin θ increases or decreases as θ increases
Solve for x : sin2 x + sin2 30° = 1
If θ = 30°, verify that: sin 3θ = 4sinθ . sin(60° - θ) sin(60° + θ)
If `sqrt(3)`sec 2θ = 2 and θ< 90°, find the value of θ
Find the length of EC.
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
a. AB is `sqrt(3)` times of BC.
B. BC is `sqrt(3)` times of BC.
In the given figure; ∠B = 90°, ∠ADB = 30°, ∠ACB = 45° and AB = 24 m. Find the length of CD.
Evaluate the following: `(3sin^2 40°)/(4cos^2 50°) - ("cosec"^2 28°)/(4sec^2 62°) + (cos10° cos25° cos45° "cosec"80°)/(2sin15° sin25° sin45° sin65° sec75°)`
If cosθ = sin60° and θ is an acute angle find the value of 1- 2 sin2θ
If secθ= cosec30° and θ is an acute angle, find the value of 4 sin2θ - 2 cos2θ.
