Advertisements
Advertisements
Question
If sin α + cosβ = 1 and α= 90°, find the value of 'β'.
Sum
Advertisements
Solution
sin α + cos β = 1
⇒ sin 90° + cos β = 1
⇒ 1 + cos β = 1
⇒ cos β = 0
⇒ cos β = cos 90°
⇒ β = 90°.
shaalaa.com
Trigonometric Equation Problem and Solution
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
If 2 sin x° − 1 = 0 and x° is an acute angle; find:
- sin x°
- x°
- cos x° and tan x°.
If sin 3A = 1 and 0 < A < 90°, find cos 2A
Solve for x : 2 cos (3x − 15°) = 1
Solve for x : tan2 (x - 5°) = 3
Solve for x : sin2 60° + cos2 (3x- 9°) = 1
If θ = 30°, verify that: sin 3θ = 4sinθ . sin(60° - θ) sin(60° + θ)
If θ < 90°, find the value of: `tan^2θ - (1)/cos^2θ`
Find the length of AD. Given: ∠ABC = 60°, ∠DBC = 45° and BC = 24 cm.
Evaluate the following: `(sin62°)/(cos28°)`
If sec2θ = cosec3θ, find the value of θ if it is known that both 2θ and 3θ are acute angles.
