Advertisements
Advertisements
Question
Solve the following equation for A, if `sqrt3` cot 2 A = 1
Advertisements
Solution
`sqrt3cot` 2 A = 1
cot 2 A = `(1)/(sqrt3)`
cot 2 A = cot 60°
2A = 60°
A = 30°
APPEARS IN
RELATED QUESTIONS
Find the value of 'A', if 2cos 3A = 1
If θ = 30°, verify that: tan2θ = `(2tanθ)/(1 - tan^2θ)`
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos2 (30° + θ) + sin2 (45° - θ)
Find the value 'x', if:
Find the value 'x', if:
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
a. AB is `sqrt(3)` times of BC.
B. BC is `sqrt(3)` times of BC.
Evaluate the following: `(sec32° cot26°)/(tan64° "cosec"58°)`
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cosec64° + sec70°
Evaluate the following: tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ)
Evaluate the following: `(sin0° sin35° sin55° sin75°)/(cos22° cos64° cos58° cos90°)`
