Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cosec64° + sec70°

Sum

cosec64° + sec70°
= cosec(90° - 26°) + sec(90° - 20°)
= sec26° + cosec20°)

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Trigonometric Equation Problem and Solution

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Chapter 27: Trigonometrical Ratios of Standard Angles - Exercise 27.3

Chapter 27 Trigonometrical Ratios of Standard Angles
Exercise 27.3 | Q 4.3

If 4 cos² x = 3 and x is an acute angle;
find the value of :
(i) x
(ii) cos² x + cot² x
(iii) cos 3x (iv) sin 2x

Solve the following equation for A, if sec 2A = 2

Solve the following equation for A, if 2 sin 3 A = 1

Calculate the value of A, if (sec 2A - 1) (cosec 3A - 1) = 0

Solve for x : cos² 30° + sin² 2x = 1

Solve for 'θ': `sin θ/(3)` = 1

If A = B = 60°, verify that: sin(A - B) = sinA cosB - cosA sinB

In the given figure, PQ = 6 cm, RQ = x cm and RP = 10 cm, find
a. cosθ
b. sin²θ- cos²θ
c. Use tanθ to find the value of RQ

If ΔABC is a right triangle such that ∠C = 90°, ∠A = 45° and BC =7units, find ∠B, AB and AC.

In the given figure, ∠B = 60°, ∠C = 30°, AB = 8 cm and BC = 24 cm. Find:
a. BE
b. AC