Advertisements
Advertisements
Question
Solve for x : sin2 x + sin2 30° = 1
Advertisements
Solution
sin2x + sin230° = 1
sin2x = 1 –sin2 30°
sin2x = 1 – `(1)/(4)`
sin2x = `(sqrt3)/(2)`
x = 60°
APPEARS IN
RELATED QUESTIONS
Solve the following equations for A, if `sqrt3` tan A = 1
Solve for x : tan2 (x - 5°) = 3
Find the value of 'A', if 2cos 3A = 1
Find the value of 'A', if `sqrt(3)cot"A"` = 1
Solve for 'θ': cot2(θ - 5)° = 3
If A = 30°, verify that cos2θ = `(1 - tan^2 θ)/(1 + tan^2 θ)` = cos4θ - sin4θ = 2cos2θ - 1 - 2sin2θ
Evaluate the following: `((sin3θ - 2sin4θ))/((cos3θ - 2cos4θ))` when 2θ = 30°
Evaluate the following: `((1 - cosθ)(1 + cosθ))/((1 - sinθ)(1 + sinθ)` if θ = 30°
Evaluate the following: sin(35° + θ) - cos(55° - θ) - tan(42° + θ) + cot(48° - θ)
Evaluate the following: `(3sin37°)/(cos53°) - (5"cosec"39°)/(sec51°) + (4tan23° tan37° tan67° tan53°)/(cos17° cos67° "cosec"73° "cosec"23°)`
