Advertisements
Advertisements
Question
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°
Advertisements
Solution
cos84° + cosec69° - cot68°
= cos(90° - 6°) + cosec(90° - 21°) - cot(90°- 22°)
= sin6° + sec21° - tan22°.
APPEARS IN
RELATED QUESTIONS
If sin 3A = 1 and 0 < A < 90°, find cos 2A
Solve for 'θ': cot2(θ - 5)° = 3
If A = 30°, verify that cos2θ = `(1 - tan^2 θ)/(1 + tan^2 θ)` = cos4θ - sin4θ = 2cos2θ - 1 - 2sin2θ
If θ < 90°, find the value of: `tan^2θ - (1)/cos^2θ`
Find:
a. BC
b. AD
c. AC
Evaluate the following: sin(35° + θ) - cos(55° - θ) - tan(42° + θ) + cot(48° - θ)
If cosθ = sin60° and θ is an acute angle find the value of 1- 2 sin2θ
If secθ= cosec30° and θ is an acute angle, find the value of 4 sin2θ - 2 cos2θ.
Prove the following: sin58° sec32° + cos58° cosec32° = 2
Prove the following: `(tan(90° - θ)cotθ)/("cosec"^2 θ)` = cos2θ
