Advertisements
Advertisements
Question
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°
Advertisements
Solution
cos84° + cosec69° - cot68°
= cos(90° - 6°) + cosec(90° - 21°) - cot(90°- 22°)
= sin6° + sec21° - tan22°.
APPEARS IN
RELATED QUESTIONS
Solve the following equations for A, if `sqrt3` tan A = 1
Solve for x : 3 tan2 (2x - 20°) = 1
Solve for 'θ': `sin θ/(3)` = 1
If tanθ= cotθ and 0°≤ θ ≤ 90°, find the value of 'θ'.
Find lengths of diagonals AC and BD. Given AB = 24 cm and ∠BAD = 60°.
Evaluate the following: `(cos34° cos35°)/(sin57° sin56°)`
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: tan77° - cot63° + sin57°
Evaluate the following: `(sin0° sin35° sin55° sin75°)/(cos22° cos64° cos58° cos90°)`
Evaluate the following: `(3sin^2 40°)/(4cos^2 50°) - ("cosec"^2 28°)/(4sec^2 62°) + (cos10° cos25° cos45° "cosec"80°)/(2sin15° sin25° sin45° sin65° sec75°)`
Evaluate the following: `(5cot5° cot15° cot25° cot35° cot45°)/(7tan45° tan55° tan65° tan75° tan85°) + (2"cosec"12° "cosec"24° cos78° cos66°)/(7sin14° sin23° sec76° sec67°)`
