Advertisements
Advertisements
Question
Prove the following: sin58° sec32° + cos58° cosec32° = 2
Sum
Advertisements
Solution
L.H.S.
= sin58° sec32° + cos58° cosec32°
= `sin(90° - 32°) xx (1)/(cos32°) + cos(90° - 32°) xx (1)/(sin32°)`
= `cos32° xx (1)/(cos32°) + sin32° xx (1)/(sin32°)`
= 1 + 1
= 2
= R.H.S.
shaalaa.com
Trigonometric Equation Problem and Solution
Is there an error in this question or solution?
