Advertisements
Advertisements
Question
Prove the following: `(tan(90° - θ)cotθ)/("cosec"^2 θ)` = cos2θ
Sum
Advertisements
Solution
L.H.S.
= `(tan(90° - θ)cotθ)/("cosec"^2 θ)`
= `(cotθ xx cotθ)/("cosec^2 θ)`
= `(cot^2 θ)/("cosec"^2 θ)`
= `((cos^2 θ)/(sin^2 θ))/((1)/(sin^2 θ)`
= cos2θ
= R.H.S.
shaalaa.com
Trigonometric Equation Problem and Solution
Is there an error in this question or solution?
