Advertisements
Advertisements
Question
Prove the following: tanθ tan(90° - θ) = cotθ cot(90° - θ)
Advertisements
Solution
L.H.S.
= tanθ tan(90° - θ)
= cot(90° - θ) x cotθ
= cotθ cot(90° - θ)
= R.H.S.
APPEARS IN
RELATED QUESTIONS
Use the given figure to find:
(i) tan θ°
(ii) θ°
(iii) sin2θ° - cos2θ°
(iv) Use sin θ° to find the value of x.
In ΔABC, ∠B = 90° , AB = y units, BC = `(sqrt3)` units, AC = 2 units and angle A = x°, find:
- sin x°
- x°
- tan x°
- use cos x° to find the value of y.
Solve the following equation for A, if 2cos2A = 1
Calculate the value of A, if (tan A - 1) (cosec 3A - 1) = 0
Solve for x : 3 tan2 (2x - 20°) = 1
Solve for x : cos `(x/(2)+10°) = (sqrt3)/(2)`
Find the value 'x', if:
A ladder is placed against a vertical tower. If the ladder makes an angle of 30° with the ground and reaches upto a height of 18 m of the tower; find length of the ladder.
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: sin65° + cot59°
If sin(θ - 15°) = cos(θ - 25°), find the value of θ if (θ-15°) and (θ - 25°) are acute angles.
