Advertisements
Advertisements
Question
Evaluate the following: `(sin36°)/(cos54°) + (sec31°)/("cosec"59°)`
Advertisements
Solution
`(sin36°)/(cos54°) + (sec31°)/("cosec"59°)`
= `(sin(90° - 54°))/(cos54°) + (sec(90° - 59°))/("cosec"59°)`
= `(cos54°)/(cos54°) + ("cosec"59°)/("cosec"59°)`
= 1 + 1
= 2.
APPEARS IN
RELATED QUESTIONS
Solve the following equation for A, if sin 3 A = `sqrt3 /2`
Solve the following equation for A, if sec 2A = 2
If sin 3A = 1 and 0 < A < 90°, find cos 2A
Find the magnitude of angle A, if 2 tan 3A cos 3A - tan 3A + 1 = 2 cos 3A
Solve for x : sin2 x + sin2 30° = 1
In a trapezium ABCD, as shown, AB ‖ DC, AD = DC = BC = 24 cm and ∠A = 30°. Find: length of AB
In the given figure, ∠B = 60°, ∠C = 30°, AB = 8 cm and BC = 24 cm. Find:
a. BE
b. AC
Find x and y, in each of the following figure:
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: sin65° + cot59°
If sec2θ = cosec3θ, find the value of θ if it is known that both 2θ and 3θ are acute angles.
