Advertisements
Advertisements
Question
Find x and y, in each of the following figure:
Advertisements
Solution
In right ΔABC,
tan30° = `"BC"/"AB"`
⇒ `(1)/sqrt(3) = x/(24 + y)` ....(i)
In right ΔDBC,
tan60° = `"BC"/"DB"`
⇒ `sqrt(3) = x/y`
⇒ x = `sqrt(3)y`
Substituting the value of x in (i), we get
`(1)/sqrt(3) = sqrt(3)/(24 + y)`
⇒ 24 + y = 3y
⇒ 2y = 24
⇒ y = 12cm
⇒ x = `sqrt(3) xx 12 = 12sqrt(3)"cm"`.
APPEARS IN
RELATED QUESTIONS
Find the value of 'A', if 2 cos A = 1
In a rectangle ABCD, AB = 20cm, ∠BAC = 60°, calculate side BC and diagonals AC and BD.
In a trapezium ABCD, as shown, AB ‖ DC, AD = DC = BC = 24 cm and ∠A = 30°. Find: length of AB
Find the value 'x', if:
If tan x° = `(5)/(12) . tan y° = (3)/(4)` and AB = 48m; find the length CD.
Evaluate the following: `(sec32° cot26°)/(tan64° "cosec"58°)`
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cosec64° + sec70°
Evaluate the following: cot20° cot40° cot45° cot50° cot70°
Evaluate the following: cos39° cos48° cos60° cosec42° cosec51°
If cos3θ = sin(θ - 34°), find the value of θ if 3θ is an acute angle.
