Advertisements
Advertisements
प्रश्न
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: sin65° + cot59°
Advertisements
उत्तर
sin65° + cot59°
= sin(90° - 25°) + cot(90° - 31°)
= cos25° + tan31°.
APPEARS IN
संबंधित प्रश्न
Solve the following equation for A, if 2cos2A = 1
Calculate the value of A, if (sec 2A - 1) (cosec 3A - 1) = 0
Find the length of AD. Given: ∠ABC = 60°, ∠DBC = 45° and BC = 24 cm.
In the given figure, ∠B = 60°, ∠C = 30°, AB = 8 cm and BC = 24 cm. Find:
a. BE
b. AC
Find x and y, in each of the following figure:
A ladder is placed against a vertical tower. If the ladder makes an angle of 30° with the ground and reaches upto a height of 18 m of the tower; find length of the ladder.
Evaluate the following: sin35° sin45° sec55° sec45°
Evaluate the following: tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ)
Evaluate the following: `(5cot5° cot15° cot25° cot35° cot45°)/(7tan45° tan55° tan65° tan75° tan85°) + (2"cosec"12° "cosec"24° cos78° cos66°)/(7sin14° sin23° sec76° sec67°)`
Prove the following: tanθ tan(90° - θ) = cotθ cot(90° - θ)
