Advertisements
Advertisements
प्रश्न
If cos3θ = sin(θ - 34°), find the value of θ if 3θ is an acute angle.
Advertisements
उत्तर
cos3θ = sin(θ - 34°)
⇒ sin(90° - 3θ) = sin(θ - 34°)
⇒ 90° - 3θ = θ - 34°
⇒ 4θ = 124°
⇒ θ = 31°.
APPEARS IN
संबंधित प्रश्न
In ΔABC, ∠B = 90° , AB = y units, BC = `(sqrt3)` units, AC = 2 units and angle A = x°, find:
- sin x°
- x°
- tan x°
- use cos x° to find the value of y.
Solve the following equation for A, if tan 3 A = 1
If sin 3A = 1 and 0 < A < 90°, find `tan^2A - (1)/(cos^2 "A")`
If θ = 30°, verify that: sin2θ = `(2tanθ)/(1 ++ tan^2θ)`
If θ = 30°, verify that: 1 - sin 2θ = (sinθ - cosθ)2
If A = B = 60°, verify that: sin(A - B) = sinA cosB - cosA sinB
If A = B = 60°, verify that: tan(A - B) = `(tan"A" - tan"B")/(1 + tan"A" tan"B"")`
In a trapezium ABCD, as shown, AB ‖ DC, AD = DC = BC = 24 cm and ∠A = 30°. Find: length of AB
Find x and y, in each of the following figure:
Evaluate the following: `(5cot5° cot15° cot25° cot35° cot45°)/(7tan45° tan55° tan65° tan75° tan85°) + (2"cosec"12° "cosec"24° cos78° cos66°)/(7sin14° sin23° sec76° sec67°)`
