Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: sin65° + cot59°

योग

sin65° + cot59°
= sin(90° - 25°) + cot(90° - 31°)
= cos25° + tan31°.

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Trigonometric Equation Problem and Solution

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अध्याय 22: Trigonometrical Ratios of Standard Angles - Exercise 27.3

अध्याय 22 Trigonometrical Ratios of Standard Angles
Exercise 27.3 | Q 4.1

If 4 sin² θ – 1 = 0 and angle θ is less than 90°, find the value of θ and hence the value of cos² θ + tan² θ.

If 2 cos (A + B) = 2 sin (A - B) = 1;
find the values of A and B.

Solve for x : cos `(x/(2)+10°) = (sqrt3)/(2)`

If θ = 30°, verify that: sin2θ = `(2tanθ)/(1 ++ tan^2θ)`

If A = 30°, verify that cos2θ = `(1 - tan^2 θ)/(1 + tan^2 θ)` = cos⁴θ - sin⁴θ = 2cos²θ - 1 - 2sin²θ

If θ = 30°, verify that: 1 - sin 2θ = (sinθ - cosθ)²

If A = B = 60°, verify that: cos(A - B) = cosA cosB + sinA sinB

Evaluate the following: `(tan42°)/(cot48°) + (cos33°)/(sin57°)`

Evaluate the following: `(2sin28°)/(cos62°) + (3cot49°)/(tan41°)`

Evaluate the following: tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ)