Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos72° - cos88°

योग

cos72° - cos88°
= cos(90° - 18°) - cos(90° - 2°)
= sin18° - sin2°.

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Trigonometric Equation Problem and Solution

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अध्याय 22: Trigonometrical Ratios of Standard Angles - Exercise 27.3

अध्याय 22 Trigonometrical Ratios of Standard Angles
Exercise 27.3 | Q 4.2

If 4 cos² x° - 1 = 0 and 0 ∠ x° ∠ 90°,
find:(i) x°
(ii) sin² x° + cos² x°
(iii) `(1)/(cos^2xx°) – (tan^2 xx°)`

If sin x + cos y = 1 and x = 30°, find the value of y

Solve for x : sin² 60° + cos² (3x- 9°) = 1

Find the value of 'A', if cosec 3A = `(2)/sqrt(3)`

In a trapezium ABCD, as shown, AB ‖ DC, AD = DC = BC = 24 cm and ∠A = 30°. Find: length of AB

Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.

Evaluate the following: `(tan42°)/(cot48°) + (cos33°)/(sin57°)`

Evaluate the following: `(2sin25° sin35° sec55° sec65°)/(5tan 29° tan45° tan61°) + (3cos20° cos50° cot70° cot40°)/(5tan20° tan50° sin70° sin40°)`

If P, Q and R are the interior angles of ΔPQR, prove that `cot(("Q" + "R")/2) = tan "P"/(2)`

Prove the following: sin²30° + cos²30° = `(1)/(2)sec60°`