Advertisements
Advertisements
प्रश्न
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos72° - cos88°
योग
Advertisements
उत्तर
cos72° - cos88°
= cos(90° - 18°) - cos(90° - 2°)
= sin18° - sin2°.
shaalaa.com
Trigonometric Equation Problem and Solution
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Solve for x : sin (x + 10°) = `(1)/(2)`
Find the value of 'A', if 2cos 3A = 1
If sin α + cosβ = 1 and α= 90°, find the value of 'β'.
Solve for 'θ': cot2(θ - 5)° = 3
Find:
a. BC
b. AD
c. AC
Find the value 'x', if:
Evaluate the following: sin31° - cos59°
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: sin53° + sec66° - sin50°
Evaluate the following: sin(35° + θ) - cos(55° - θ) - tan(42° + θ) + cot(48° - θ)
If sec2θ = cosec3θ, find the value of θ if it is known that both 2θ and 3θ are acute angles.
