Advertisements
Advertisements
प्रश्न
Find the value of 'A', if `sqrt(3)cot"A"` = 1
Advertisements
उत्तर
`sqrt(3)cot"A"` = 1
⇒ cot A = `(1)/sqrt(3)`
⇒ cot A = cot60°
⇒ A = 60°.
APPEARS IN
संबंधित प्रश्न
From the given figure,
find:
(i) cos x°
(ii) x°
(iii) `(1)/(tan^2 xx°) – (1)/(sin^2xx°)`
(iv) Use tan xo, to find the value of y.
Calculate the value of A, if (cosec 2A - 2) (cot 3A - 1) = 0
Find the magnitude of angle A, if 2 tan 3A cos 3A - tan 3A + 1 = 2 cos 3A
Find the value of 'A', if cot 3A = 1
If θ < 90°, find the value of: `tan^2θ - (1)/cos^2θ`
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos 3θ
In the given figure, ∠B = 60°, ∠C = 30°, AB = 8 cm and BC = 24 cm. Find:
a. BE
b. AC
Find the value 'x', if:
Evaluate the following: cot20° cot40° cot45° cot50° cot70°
If secθ= cosec30° and θ is an acute angle, find the value of 4 sin2θ - 2 cos2θ.
