Advertisements
Advertisements
प्रश्न
Find the value of 'A', if cot 3A = 1
बेरीज
Advertisements
उत्तर
cot 3A = 1
⇒ cot 3A = cot 45°
⇒ 3A = 45°
⇒ A = 15°.
shaalaa.com
Trigonometric Equation Problem and Solution
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Calculate the value of A, if (sin A - 1) (2 cos A - 1) = 0
Solve for x : sin (x + 10°) = `(1)/(2)`
Solve for x : cos2 30° + sin2 2x = 1
Find the value of 'A', if 2cos 3A = 1
Find the value of 'A', if (2 - cosec 2A) cos 3A = 0
If θ = 30°, verify that: sin2θ = `(2tanθ)/(1 ++ tan^2θ)`
If θ < 90°, find the value of: sin2θ + cos2θ
Find the value of 'x' in each of the following:
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
a. AB is `sqrt(3)` times of BC.
B. BC is `sqrt(3)` times of BC.
Prove the following: `(tan(90° - θ)cotθ)/("cosec"^2 θ)` = cos2θ
