Advertisements
Advertisements
प्रश्न
In the given figure, AB and EC are parallel to each other. Sides AD and BC are 1.5 cm each and are perpendicular to AB. Given that ∠AED = 45° and ∠ACD = 30°. Find:
a. AB
b. AC
c. AE
Advertisements
उत्तर

a. In right ΔADC,
tan30° = `"AD"/"DC"`
⇒ `(1)/sqrt(3) = (1.5)/"DC"`
⇒ DC = `1.5sqrt(3)`
Since AB || DC and AD ⊥ EC, ABCD is a parallelogram and hence opposite sides are equal.
⇒ AB
= DC
= `1.5sqrt(3)"cm"`.
b. In right ΔADC,
sin30° = `"AD"/"AC"`
⇒ `(1)/(2) = (1.5)/"AC"`
⇒ AC
= 2 x 1.5
= 3cm.
c. In right ΔADE,
sin45° = `"AD"/"AE"`
⇒ `(1)/sqrt(2) = (1.5)/"AE"`
⇒ AE = `1.5sqrt(2)`.
APPEARS IN
संबंधित प्रश्न
From the given figure,
find:
(i) cos x°
(ii) x°
(iii) `(1)/(tan^2 xx°) – (1)/(sin^2xx°)`
(iv) Use tan xo, to find the value of y.
State for any acute angle θ whether tan θ increases or decreases as θ decreases.
Solve the following equation for A, if tan 3 A = 1
Solve for x : sin2 x + sin2 30° = 1
If θ = 30°, verify that: 1 - sin 2θ = (sinθ - cosθ)2
Find the value of: `sqrt((1 - sin^2 60°)/(1 + sin^2 60°)` If 3 tan2θ - 1 = 0, find the value
a. cosθ
b. sinθ
In a rectangle ABCD, AB = 20cm, ∠BAC = 60°, calculate side BC and diagonals AC and BD.
Find:
a. BC
b. AD
c. AC
Evaluate the following: `(tan12°)/(cot78°)`
If secθ= cosec30° and θ is an acute angle, find the value of 4 sin2θ - 2 cos2θ.
