Advertisements
Advertisements
प्रश्न
In the given figure, AB and EC are parallel to each other. Sides AD and BC are 1.5 cm each and are perpendicular to AB. Given that ∠AED = 45° and ∠ACD = 30°. Find:
a. AB
b. AC
c. AE
Advertisements
उत्तर

a. In right ΔADC,
tan30° = `"AD"/"DC"`
⇒ `(1)/sqrt(3) = (1.5)/"DC"`
⇒ DC = `1.5sqrt(3)`
Since AB || DC and AD ⊥ EC, ABCD is a parallelogram and hence opposite sides are equal.
⇒ AB
= DC
= `1.5sqrt(3)"cm"`.
b. In right ΔADC,
sin30° = `"AD"/"AC"`
⇒ `(1)/(2) = (1.5)/"AC"`
⇒ AC
= 2 x 1.5
= 3cm.
c. In right ΔADE,
sin45° = `"AD"/"AE"`
⇒ `(1)/sqrt(2) = (1.5)/"AE"`
⇒ AE = `1.5sqrt(2)`.
APPEARS IN
संबंधित प्रश्न
If 2 cos 2A = `sqrt3` and A is acute,
find:
(i) A
(ii) sin 3A
(iii) sin2 (75° - A) + cos2 (45° +A)
If A = B = 60°, verify that: cos(A - B) = cosA cosB + sinA sinB
Find the value of 'x' in each of the following:
Find the value 'x', if:
Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.
Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.
In the given figure, if tan θ = `(5)/(13), tan α = (3)/(5)` and RS = 12m, find the value of 'h'.
Find x and y, in each of the following figure:
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: sin65° + cot59°
Prove the following: sin58° sec32° + cos58° cosec32° = 2
