Advertisements
Advertisements
प्रश्न
If tan x° = `(5)/(12) . tan y° = (3)/(4)` and AB = 48m; find the length CD.
Advertisements
उत्तर

tan x = `"CD"/"AC"`
⇒ `(5)/(12) = "CD"/"AC"`
⇒ 5 x AC = 12 x CD
⇒ 5(AB + BC) = 12CD
⇒ 5(48 + BC) = 12CD
⇒ 48 + BC = `(12"CD")/(5)` ....(i)
tan y = `"CD"/"BC"`
⇒ `(3)/(4) = "CD"/"BC"`
⇒ 3BC = 4CD
⇒ BC = `(6"CD")/(3)` ....(ii)
Substituting (ii) in (i), we have
`48 + (4"CD")/(3) = (12"CD")/(5)`
⇒ `(12"CD")/(5) - (4"CD")/(3)` = 48
⇒ `(36"CD" - 20"CD")/(15)` = 48
⇒ 16CD = 720
⇒ CD = 45m.
APPEARS IN
संबंधित प्रश्न
If 2 cos 2A = `sqrt3` and A is acute,
find:
(i) A
(ii) sin 3A
(iii) sin2 (75° - A) + cos2 (45° +A)
Solve the following equation for A, if tan 3 A = 1
If sin 3A = 1 and 0 < A < 90°, find `tan^2A - (1)/(cos^2 "A")`
Find the magnitude of angle A, if 2 tan 3A cos 3A - tan 3A + 1 = 2 cos 3A
Solve for x : sin2 60° + cos2 (3x- 9°) = 1
Evaluate the following: `((sin3θ - 2sin4θ))/((cos3θ - 2cos4θ))` when 2θ = 30°
If θ < 90°, find the value of: sin2θ + cos2θ
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
a. AB is `sqrt(3)` times of BC.
B. BC is `sqrt(3)` times of BC.
Evaluate the following: `(sec32° cot26°)/(tan64° "cosec"58°)`
Evaluate the following: cosec 54° - sec 36°
