Advertisements
Advertisements
प्रश्न
Find the value 'x', if:
Advertisements
उत्तर
In right ΔACB,
tan30° = `"BC"/"AC"`
⇒ `(1)/sqrt(3) = (10)/"AC"`
⇒ AC = `10sqrt(3)"cm"`
Now,
In right ΔACD,
sin x = `"AC"/"AD"`
⇒ sin x = `(10sqrt(3))/(20)`
⇒ sin x = `sqrt(3)/(2)`
⇒ sin x = sin60°
⇒ x = 60°.
APPEARS IN
संबंधित प्रश्न
Solve the following equation for A, if sin 3 A = `sqrt3 /2`
If 2 sin x° − 1 = 0 and x° is an acute angle; find:
- sin x°
- x°
- cos x° and tan x°.
If sin 3A = 1 and 0 < A < 90°, find sin A
Evaluate the following: `((sin3θ - 2sin4θ))/((cos3θ - 2cos4θ))` when 2θ = 30°
In the given figure, if tan θ = `(5)/(13), tan α = (3)/(5)` and RS = 12m, find the value of 'h'.
Evaluate the following: `(sec32° cot26°)/(tan64° "cosec"58°)`
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: sin53° + sec66° - sin50°
Evaluate the following: sin35° sin45° sec55° sec45°
Evaluate the following: sin(35° + θ) - cos(55° - θ) - tan(42° + θ) + cot(48° - θ)
Evaluate the following: `(3sin^2 40°)/(4cos^2 50°) - ("cosec"^2 28°)/(4sec^2 62°) + (cos10° cos25° cos45° "cosec"80°)/(2sin15° sin25° sin45° sin65° sec75°)`
