Advertisements
Advertisements
प्रश्न
Find the value 'x', if:
Advertisements
उत्तर
In right ΔACB,
tan30° = `"BC"/"AC"`
⇒ `(1)/sqrt(3) = (10)/"AC"`
⇒ AC = `10sqrt(3)"cm"`
Now,
In right ΔACD,
sin x = `"AC"/"AD"`
⇒ sin x = `(10sqrt(3))/(20)`
⇒ sin x = `sqrt(3)/(2)`
⇒ sin x = sin60°
⇒ x = 60°.
APPEARS IN
संबंधित प्रश्न
If sin 3A = 1 and 0 < A < 90°, find sin A
From the given figure,
find:
(i) cos x°
(ii) x°
(iii) `(1)/(tan^2 xx°) – (1)/(sin^2xx°)`
(iv) Use tan xo, to find the value of y.
State for any acute angle θ whether cos θ increases or decreases as θ increases.
Calculate the value of A, if cos 3A. (2 sin 2A - 1) = 0
Evaluate the following: `((sin3θ - 2sin4θ))/((cos3θ - 2cos4θ))` when 2θ = 30°
Evaluate the following: `((1 - cosθ)(1 + cosθ))/((1 - sinθ)(1 + sinθ)` if θ = 30°
If A = B = 60°, verify that: sin(A - B) = sinA cosB - cosA sinB
In a trapezium ABCD, as shown, AB ‖ DC, AD = DC = BC = 24 cm and ∠A = 30°. Find: length of AB
Find the value 'x', if:
Find x and y, in each of the following figure:
