Advertisements
Advertisements
प्रश्न
If cosθ = sin60° and θ is an acute angle find the value of 1- 2 sin2θ
Advertisements
उत्तर
cosθ = sin60°
⇒ cosθ = `sqrt(3)/(2)`
⇒ cosθ = cos30°
⇒ θ = 30°
Now,
1 - 2sin2θ
= 1 - 2sin230°
= `1 - 2(1/2)^2`
= `1 - 2 xx (1)/(4)`
= `1 - (1)/(2)`
= `(1)/(2)`.
APPEARS IN
संबंधित प्रश्न
If 4 sin2 θ – 1 = 0 and angle θ is less than 90°, find the value of θ and hence the value of cos2 θ + tan2 θ.
If 4 cos2 x = 3 and x is an acute angle;
find the value of :
(i) x
(ii) cos2 x + cot2 x
(iii) cos 3x (iv) sin 2x
In ΔABC, ∠B = 90° , AB = y units, BC = `(sqrt3)` units, AC = 2 units and angle A = x°, find:
- sin x°
- x°
- tan x°
- use cos x° to find the value of y.
Calculate the value of A, if cos 3A. (2 sin 2A - 1) = 0
Solve for x : 3 tan2 (2x - 20°) = 1
If `sqrt(3)`sec 2θ = 2 and θ< 90°, find the value of θ
Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.
Evaluate the following: `(sin25° cos43°)/(sin47° cos 65°)`
Evaluate the following: `(cos34° cos35°)/(sin57° sin56°)`
Evaluate the following: `(3sin37°)/(cos53°) - (5"cosec"39°)/(sec51°) + (4tan23° tan37° tan67° tan53°)/(cos17° cos67° "cosec"73° "cosec"23°)`
