Advertisements
Advertisements
प्रश्न
Calculate the value of A, if (sec 2A - 1) (cosec 3A - 1) = 0
Advertisements
उत्तर
( sec 2A – 1) ( cosec 3A – 1) = 0
sec 2A – 1 = 0 and cosec 3A – 1 = 0
sec 2A = 1 and cosec 3A = 1
sec 2A = sec0° and cosec 3A = cosec90°
A = 0° and A = 30°
APPEARS IN
संबंधित प्रश्न
If sin x + cos y = 1 and x = 30°, find the value of y
If sin 3A = 1 and 0 < A < 90°, find cos 2A
Solve for x : cos `(x)/(3) –1` = 0
Solve for x : sin (x + 10°) = `(1)/(2)`
Solve for 'θ': `sin θ/(3)` = 1
Find the value of 'x' in each of the following:
Find x and y, in each of the following figure:
Evaluate the following: `(sec32° cot26°)/(tan64° "cosec"58°)`
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°
Evaluate the following: `(sin0° sin35° sin55° sin75°)/(cos22° cos64° cos58° cos90°)`
