Advertisements
Advertisements
प्रश्न
Find the magnitude of angle A, if 2 sin A cos A - cos A - 2 sin A + 1 = 0
Advertisements
उत्तर
2 sin A cos A – cos A – 2 sin A + 1 = 0
2 sin A cos A – cos A = 2 sin A – 1
(2 sin A – 1) cos A – (2 sin A – 1) = 0
(2 sin A – 1) = 0 and cos A = 1
sin A =`(1)/(2)` and cos A = cos 0°
A = 30° and A = 0°
APPEARS IN
संबंधित प्रश्न
Solve the following equation for A, if sin 3 A = `sqrt3 /2`
Solve for x : 2 cos 3x - 1 = 0
State for any acute angle θ whether tan θ increases or decreases as θ decreases.
Solve the following equation for A, if `sqrt3` cot 2 A = 1
Solve for x : cos (2x - 30°) = 0
Solve for x : 3 tan2 (2x - 20°) = 1
If `sqrt(2) = 1.414 and sqrt(3) = 1.732`, find the value of the following correct to two decimal places tan60°
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos 3θ
Find the value of 'x' in each of the following:
Evaluate the following: `(2sin25° sin35° sec55° sec65°)/(5tan 29° tan45° tan61°) + (3cos20° cos50° cot70° cot40°)/(5tan20° tan50° sin70° sin40°)`
