Advertisements
Advertisements
प्रश्न
Use the given figure to find:
(i) tan θ°
(ii) θ°
(iii) sin2θ° - cos2θ°
(iv) Use sin θ° to find the value of x.
Advertisements
उत्तर
(i) tan θ° = `(5)/(5) = 1`
(ii) tan θ° = 1
tan θ° = tan 45°
θ° = 45°
(iii) sin2θ° – cos2θ° = sin245° – cos2 45°
= `(1/sqrt2)^2 – (1/sqrt2)^2`
= 0
(iv) sinθ° = `(5)/(x)`
sin 45° = `(5)/(x)`
x = `(5)/(sin45°)`
x = `(5)/(1/sqrt2)`
x = 5`sqrt2`
APPEARS IN
संबंधित प्रश्न
Solve the following equation for A, if 2 sin 3 A = 1
Find the magnitude of angle A, if tan A - 2 cos A tan A + 2 cos A - 1 = 0
Solve for x : 2 cos (3x − 15°) = 1
Solve for x : tan2 (x - 5°) = 3
Solve for x : sin2 x + sin2 30° = 1
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos 3θ
A ladder is placed against a vertical tower. If the ladder makes an angle of 30° with the ground and reaches upto a height of 18 m of the tower; find length of the ladder.
Evaluate the following: `(sin36°)/(cos54°) + (sec31°)/("cosec"59°)`
Evaluate the following: tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ)
If sec2θ = cosec3θ, find the value of θ if it is known that both 2θ and 3θ are acute angles.
