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प्रश्न
Use the given figure to find:
(i) tan θ°
(ii) θ°
(iii) sin2θ° - cos2θ°
(iv) Use sin θ° to find the value of x.
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उत्तर
(i) tan θ° = `(5)/(5) = 1`
(ii) tan θ° = 1
tan θ° = tan 45°
θ° = 45°
(iii) sin2θ° – cos2θ° = sin245° – cos2 45°
= `(1/sqrt2)^2 – (1/sqrt2)^2`
= 0
(iv) sinθ° = `(5)/(x)`
sin 45° = `(5)/(x)`
x = `(5)/(sin45°)`
x = `(5)/(1/sqrt2)`
x = 5`sqrt2`
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