Advertisements
Advertisements
प्रश्न
Solve for x : 2 cos (3x − 15°) = 1
Advertisements
उत्तर
2 cos(3x –15°) = 1
cos (3x – 15°) = `(1)/(2)`
cos (3x – 15°) = cos 60°
3x – 15° = 60°
3x = 75°
x = 25°
संबंधित प्रश्न
Solve the following equations for A, if `sqrt3` tan A = 1
Find the value of 'A', if 2 sin 2A = 1
If θ = 30°, verify that: tan2θ = `(2tanθ)/(1 - tan^2θ)`
In a right triangle ABC, right angled at C, if ∠B = 60° and AB = 15units, find the remaining angles and sides.
Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.
In the given figure; ∠B = 90°, ∠ADB = 30°, ∠ACB = 45° and AB = 24 m. Find the length of CD.
Evaluate the following: `(tan12°)/(cot78°)`
Evaluate the following: cosec 54° - sec 36°
Evaluate the following: `(3sin37°)/(cos53°) - (5"cosec"39°)/(sec51°) + (4tan23° tan37° tan67° tan53°)/(cos17° cos67° "cosec"73° "cosec"23°)`
If sin(θ - 15°) = cos(θ - 25°), find the value of θ if (θ-15°) and (θ - 25°) are acute angles.
