Advertisements
Advertisements
प्रश्न
Solve for x : 2 cos (3x − 15°) = 1
Advertisements
उत्तर
2 cos(3x –15°) = 1
cos (3x – 15°) = `(1)/(2)`
cos (3x – 15°) = cos 60°
3x – 15° = 60°
3x = 75°
x = 25°
APPEARS IN
संबंधित प्रश्न
If sin x + cos y = 1 and x = 30°, find the value of y
Solve for x : tan2 (x - 5°) = 3
If `sqrt(3)`sec 2θ = 2 and θ< 90°, find the value of θ
Find the value of: `sqrt((1 - sin^2 60°)/(1 + sin^2 60°)` If 3 tan2θ - 1 = 0, find the value
a. cosθ
b. sinθ
In a right triangle ABC, right angled at C, if ∠B = 60° and AB = 15units, find the remaining angles and sides.
Find the value of 'x' in each of the following:
Find:
a. BC
b. AD
c. AC
Evaluate the following: `(tan12°)/(cot78°)`
Evaluate the following: `(3sin^2 40°)/(4cos^2 50°) - ("cosec"^2 28°)/(4sec^2 62°) + (cos10° cos25° cos45° "cosec"80°)/(2sin15° sin25° sin45° sin65° sec75°)`
If tan4θ = cot(θ + 20°), find the value of θ if 4θ is an acute angle.
