Advertisements
Advertisements
प्रश्न
Find the value of 'A', if 2 sin 2A = 1
Advertisements
उत्तर
2 sin 2A = 1
⇒ sin 2A = `(1)/(2)`
⇒ sin 2A = sin30°
⇒ 2A = 30°
⇒ A = 15°.
APPEARS IN
संबंधित प्रश्न
In ΔABC, ∠B = 90° , AB = y units, BC = `(sqrt3)` units, AC = 2 units and angle A = x°, find:
- sin x°
- x°
- tan x°
- use cos x° to find the value of y.
Solve the following equations for A, if `sqrt3` tan A = 1
Solve the following equation for A, if 2 sin A = 1
Calculate the value of A, if (cosec 2A - 2) (cot 3A - 1) = 0
Find the magnitude of angle A, if tan A - 2 cos A tan A + 2 cos A - 1 = 0
If A = B = 60°, verify that: sin(A - B) = sinA cosB - cosA sinB
In the given figure, PQ = 6 cm, RQ = x cm and RP = 10 cm, find
a. cosθ
b. sin2θ- cos2θ
c. Use tanθ to find the value of RQ
If ΔABC is a right triangle such that ∠C = 90°, ∠A = 45° and BC =7units, find ∠B, AB and AC.
Find the value 'x', if:
If A + B = 90°, prove that `(tan"A" tan"B" + tan"A" cot"B")/(sin"A" sec"B") - (sin^2"B")/(cos^2"A")` = tan2A
