Advertisements
Advertisements
प्रश्न
Solve for x : sin2 60° + cos2 (3x- 9°) = 1
Advertisements
उत्तर
sin260° + cos2(3x – 9°) = 1
cos2(3x – 9°) = 1 – sin260°
cos2(3x – 9°) = 1 – `(3)/(4)`
cos2(3x – 9°) = `(1)/(4)`
cos2(3x – 9°) = `(1)/(2)`
3x – 9° = 60°
3x = 69°
x = 23°
APPEARS IN
संबंधित प्रश्न
If sin x + cos y = 1 and x = 30°, find the value of y
If sin 3A = 1 and 0 < A < 90°, find cos 2A
If θ = 30°, verify that: 1 - sin 2θ = (sinθ - cosθ)2
If A = B = 60°, verify that: cos(A - B) = cosA cosB + sinA sinB
A ladder is placed against a vertical tower. If the ladder makes an angle of 30° with the ground and reaches upto a height of 18 m of the tower; find length of the ladder.
Evaluate the following: `(tan12°)/(cot78°)`
Evaluate the following: sin31° - cos59°
Evaluate the following: sin28° sec62° + tan49° tan41°
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°
Evaluate the following: `(2sin25° sin35° sec55° sec65°)/(5tan 29° tan45° tan61°) + (3cos20° cos50° cot70° cot40°)/(5tan20° tan50° sin70° sin40°)`
