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प्रश्न
Solve for x : sin2 60° + cos2 (3x- 9°) = 1
बेरीज
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उत्तर
sin260° + cos2(3x – 9°) = 1
cos2(3x – 9°) = 1 – sin260°
cos2(3x – 9°) = 1 – `(3)/(4)`
cos2(3x – 9°) = `(1)/(4)`
cos2(3x – 9°) = `(1)/(2)`
3x – 9° = 60°
3x = 69°
x = 23°
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