Advertisements
Advertisements
प्रश्न
Find the value 'x', if:
Advertisements
उत्तर
In right ΔABC,
sin x = `"AB"/"BC"`
⇒ sin x = `sqrt(3)/(2)`
⇒ sin x = sin60°
⇒ x = 60°.
APPEARS IN
संबंधित प्रश्न
Solve for x : tan2 (x - 5°) = 3
Find the value of 'A', if 2cos 3A = 1
If θ = 15°, find the value of: cos3θ - sin6θ + 3sin(5θ + 15°) - 2 tan23θ
Find the value of: `sqrt((1 - sin^2 60°)/(1 + sin^2 60°)` If 3 tan2θ - 1 = 0, find the value
a. cosθ
b. sinθ
In a right triangle ABC, right angled at C, if ∠B = 60° and AB = 15units, find the remaining angles and sides.
The perimeter of a rhombus is 100 cm and obtuse angle of it is 120°. Find the lengths of its diagonals.
In the given figure; ∠B = 90°, ∠ADB = 30°, ∠ACB = 45° and AB = 24 m. Find the length of CD.
Evaluate the following: sin28° sec62° + tan49° tan41°
Evaluate the following: `(sin36°)/(cos54°) + (sec31°)/("cosec"59°)`
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°
