Advertisements
Advertisements
प्रश्न
Find the value of 'x' in each of the following:
Advertisements
उत्तर
From the figure, we have
sin x = `"BC"/"AC"`
⇒ sin x = `(15/sqrt(2))/(15)`
⇒ sin x = `(1)/sqrt(2)`
⇒ sin x = sin45°
⇒ x = 45°.
APPEARS IN
संबंधित प्रश्न
Calculate the value of A, if (tan A - 1) (cosec 3A - 1) = 0
Calculate the value of A, if (cosec 2A - 2) (cot 3A - 1) = 0
If θ = 15°, find the value of: cos3θ - sin6θ + 3sin(5θ + 15°) - 2 tan23θ
Find lengths of diagonals AC and BD. Given AB = 24 cm and ∠BAD = 60°.
Find:
a. BC
b. AD
c. AC
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°
Evaluate the following: `(sin0° sin35° sin55° sin75°)/(cos22° cos64° cos58° cos90°)`
Evaluate the following: `(3sin^2 40°)/(4cos^2 50°) - ("cosec"^2 28°)/(4sec^2 62°) + (cos10° cos25° cos45° "cosec"80°)/(2sin15° sin25° sin45° sin65° sec75°)`
Prove the following: tanθ tan(90° - θ) = cotθ cot(90° - θ)
Prove the following: sin230° + cos230° = `(1)/(2)sec60°`
