Advertisements
Advertisements
प्रश्न
Find the value of 'x' in each of the following:
Advertisements
उत्तर
From the figure, we have
sin x = `"BC"/"AC"`
⇒ sin x = `(15/sqrt(2))/(15)`
⇒ sin x = `(1)/sqrt(2)`
⇒ sin x = sin45°
⇒ x = 45°.
APPEARS IN
संबंधित प्रश्न
If 4 cos2 x = 3 and x is an acute angle;
find the value of :
(i) x
(ii) cos2 x + cot2 x
(iii) cos 3x (iv) sin 2x
State for any acute angle θ whether cos θ increases or decreases as θ increases.
State for any acute angle θ whether tan θ increases or decreases as θ decreases.
Solve for x : 2 cos (3x − 15°) = 1
Solve for x : cos `(x/(2)+10°) = (sqrt3)/(2)`
Solve for x : sin2 60° + cos2 (3x- 9°) = 1
In the given figure, ∠B = 60°, ∠C = 30°, AB = 8 cm and BC = 24 cm. Find:
a. BE
b. AC
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
a. AB is `sqrt(3)` times of BC.
B. BC is `sqrt(3)` times of BC.
Evaluate the following: sin31° - cos59°
Prove the following: tanθ tan(90° - θ) = cotθ cot(90° - θ)
