Find the value of 'x' in each of the following:

योग

From the figure, we have

sin x = `"BC"/"AC"`

⇒ sin x = `(15/sqrt(2))/(15)`

⇒ sin x = `(1)/sqrt(2)`
⇒ sin x = sin45°
⇒ x = 45°.

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Trigonometric Equation Problem and Solution

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अध्याय 22: Trigonometrical Ratios of Standard Angles - Exercise 27.2

अध्याय 22 Trigonometrical Ratios of Standard Angles
Exercise 27.2 | Q 1.4

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