Advertisements
Advertisements
प्रश्न
Evaluate the following: cot27° - tan63°
Advertisements
उत्तर
cot27° - tan63°
= cot(90° - 63°) - tan63°
= tan63° - tan63°
= 0.
APPEARS IN
संबंधित प्रश्न
If 2 sin x° − 1 = 0 and x° is an acute angle; find:
- sin x°
- x°
- cos x° and tan x°.
Find the magnitude of angle A, if 2 sin A cos A - cos A - 2 sin A + 1 = 0
Solve the following equation for A, if sec 2A = 2
Calculate the value of A, if (sec 2A - 1) (cosec 3A - 1) = 0
Find the value of 'A', if cot 3A = 1
Solve for 'θ': `sec(θ/2 + 10°) = (2)/sqrt(3)`
If `sqrt(2) = 1.414 and sqrt(3) = 1.732`, find the value of the following correct to two decimal places tan60°
If θ = 15°, find the value of: cos3θ - sin6θ + 3sin(5θ + 15°) - 2 tan23θ
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
a. AB is `sqrt(3)` times of BC.
B. BC is `sqrt(3)` times of BC.
The perimeter of a rhombus is 100 cm and obtuse angle of it is 120°. Find the lengths of its diagonals.
