Advertisements
Advertisements
प्रश्न
Evaluate the following: sin35° sin45° sec55° sec45°
Advertisements
उत्तर
sin35° sin45° sec55° sec45°
= `sin(90° - 55°) xx (1)/sqrt(2) xx (1)/(cos55°) xx sqrt(2)`
= `cos55° xx (1)/(cos55°) xx (1)/sqrt(2) xx sqrt(2)`
= 1.
APPEARS IN
संबंधित प्रश्न
Find the magnitude of angle A, if 2 tan 3A cos 3A - tan 3A + 1 = 2 cos 3A
Solve for x : cos `(x/(2)+10°) = (sqrt3)/(2)`
Find the value of 'A', if cot 3A = 1
Find the value of 'A', if (2 - cosec 2A) cos 3A = 0
If θ = 30°, verify that: sin2θ = `(2tanθ)/(1 ++ tan^2θ)`
Evaluate the following: `((sin3θ - 2sin4θ))/((cos3θ - 2cos4θ))` when 2θ = 30°
If θ < 90°, find the value of: `tan^2θ - (1)/cos^2θ`
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos2 (30° + θ) + sin2 (45° - θ)
Find the value 'x', if:
If secθ= cosec30° and θ is an acute angle, find the value of 4 sin2θ - 2 cos2θ.
