Advertisements
Advertisements
प्रश्न
In the given figure, if tan θ = `(5)/(13), tan α = (3)/(5)` and RS = 12m, find the value of 'h'.
Advertisements
उत्तर
tan θ = `"PQ"/"QS"`
⇒ `(5)/(13) = "h"/"QS"`
⇒ 5 x QS = 13h
⇒ 5(QR + RS) = 13h
⇒ 5(QR + 12) = 13h
⇒ QR + 12 = `(13"h")/(5)` ....(i)
tan α = `"PQ"/"QR"`
⇒ `(3)/(5) = "h"/"QR"`
⇒ 3 x QR = 5h
⇒ QR = `(5"h")/(3)` ....(ii)
Substituting (ii) in (i), we have
`(5"h")/(3) + 12 = (13"h")/(3)`
⇒ `(13"h")/(5) - (5"h")/(3)` = 12
⇒ `(39"h" - 25"h")/(15)` = 12
⇒ 14h = 180
⇒ h = 12.86m.
APPEARS IN
संबंधित प्रश्न
If 4 cos2 x° - 1 = 0 and 0 ∠ x° ∠ 90°,
find:(i) x°
(ii) sin2 x° + cos2 x°
(iii) `(1)/(cos^2xx°) – (tan^2 xx°)`
If 2 cos 2A = `sqrt3` and A is acute,
find:
(i) A
(ii) sin 3A
(iii) sin2 (75° - A) + cos2 (45° +A)
In a trapezium ABCD, as shown, AB ‖ DC, AD = DC = BC = 24 cm and ∠A = 30°. Find: length of AB
Find the value 'x', if:
Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.
Evaluate the following: sin22° cos44° - sin46° cos68°
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos72° - cos88°
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°
If sin(θ - 15°) = cos(θ - 25°), find the value of θ if (θ-15°) and (θ - 25°) are acute angles.
If A + B = 90°, prove that `(tan"A" tan"B" + tan"A" cot"B")/(sin"A" sec"B") - (sin^2"B")/(cos^2"A")` = tan2A
