Advertisements
Advertisements
Question
If 2 cos (A + B) = 2 sin (A - B) = 1;
find the values of A and B.
Advertisements
Solution
2 cos (A + B) = 1
cos (A + B) = `(1)/(2)`
cos (A+B) = cos 60°
A + B = 60° ........( 1)
2 sin (A – B) = 1
2 sin (A – B) = `(1)/(2)`
A – B = 30° ........(2)
Adding (1) and (2)
A + B + A – B = 60° + 30°
2A = 90°
A = 45°
A + B = 60°
B = 60° – A
B = 60 – 45°
B = 15°
APPEARS IN
RELATED QUESTIONS
State for any acute angle θ whether sin θ increases or decreases as θ increases
Solve for x : cos `(x)/(3) –1` = 0
If A = 30°, verify that cos2θ = `(1 - tan^2 θ)/(1 + tan^2 θ)` = cos4θ - sin4θ = 2cos2θ - 1 - 2sin2θ
If θ < 90°, find the value of: `tan^2θ - (1)/cos^2θ`
Find the value of 'x' in each of the following:
Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.
Find x and y, in each of the following figure:
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: sin65° + cot59°
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: tan77° - cot63° + sin57°
If sec2θ = cosec3θ, find the value of θ if it is known that both 2θ and 3θ are acute angles.
