Advertisements
Advertisements
Question
Solve the following equation by factorization
(x – 4)2 + 52 = 132
Advertisements
Solution
(x – 4)2 + 52 = 132
x2 – 8x + 16 + 25 = 169
x2 - 8x + 41 - 169 = 0
⇒ x2 - 8x - 128 = 0
⇒ x2 - 16x + 8x - 128 = 0
⇒ x (x - 16) + 8(x - 16) = 0
⇒ (x - 16) (x + 8) = 0
Either x - 16 = 0,
then x = 16
or
x + 8 = 0,
then x = -8
Hence x = 16, -8.
APPEARS IN
RELATED QUESTIONS
Solve for x :
`1/(2x - 3) + 1/(x - 5) = 1 1/9 , X != 3/2, 5`
Solve the following quadratic equations by factorization:
3x2 − 14x − 5 = 0
Solve 2x2 – 9x + 10 =0; when x ∈ Q
`3x^2-x-2=0`
If the equation x2 + 4x + k = 0 has real and distinct roots, then
If y = 1 is a common root of the equations \[a y^2 + ay + 3 = 0 \text { and } y^2 + y + b = 0\], then ab equals
Solve equation using factorisation method:
`2x^2 - 1/2x = 0`
Solve the following by reducing them to quadratic form:
`sqrt(y + 1) + sqrt(2y - 5) = 3, y ∈ "R".`
Solve the following equation by factorization
3x2= x + 4
If x = –2 is the common solution of quadratic equations ax2 + x – 3a = 0 and x2 + bx + b = 0, then find the value of a2b.
