Advertisements
Advertisements
Question
Solve the following equation by factorization
`(2)/(3)x^2 - (1)/(3)x` = 1
Advertisements
Solution
`(2)/(3)x^2 - (1)/(3)x` = 1
⇒ 2x2 - x = 3
⇒ 2x2 - x - 3 = 0
⇒ 2x2 - 3x + 2x - 3 = 0
⇒ x(2x - 3) + 1(2x - 3) = 0
⇒ (2x - 3) (x + 1) = 0
Either 2x - 3 = 0,
then 2x = 3
⇒ x = `(3)/(2)`
or
x + 1 = 0,
then x = -1
Hence x = `(3)/(2)`, -1.
APPEARS IN
RELATED QUESTIONS
A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was Rs 750. We would like to find out the number of toys produced on that day.
Solve the following quadratic equations by factorization:
(2x + 3)(3x − 7) = 0
Solve x2 – 4x – 12 =0; when x ∈ I
Solve the following quadratic equation by
factorisation.
5m2 = 22m + 15
Solve the following quadratic equations by factorization:
\[16x - \frac{10}{x} = 27\]
If one root the equation 2x2 + kx + 4 = 0 is 2, then the other root is
Solve the following equation:
(2x+3) (3x-7) = 0
A two digit positive number is such that the product of its digits is 6. If 9 is added to the number, the digits interchange their places. Find the number.
Solve the following equation by factorization
`a/(ax - 1) + b/(bx - 1) = a + b, a + b ≠ 0, ab ≠ 0`
2x articles cost Rs. (5x + 54) and (x + 2) similar articles cost Rs. (10x – 4), find x.
