Advertisements
Advertisements
Question
Solve the following equation by factorization
3x2= x + 4
Advertisements
Solution
3x2 = x + 4
⇒ 3x2 – x – 4 = 0
⇒ 3x2 – 4x + 3x – 4 = 0
⇒ x (3x - 4) + 1 (3x - 4) = 0
⇒ (3x - 4) (x + 1) = 0
Either 3x - 4 = 0,
then 3x = 4
⇒ x = `(4)/(3)`
or
x + 1 = 0,
then x = -1
Hence x = `(4)/(3), -1`.
APPEARS IN
RELATED QUESTIONS
Solve the following quadratic equation for x:
`x^2+(a/(a+b)+(a+b)/a)x+1=0`
Solve for x :
`1/(2x - 3) + 1/(x - 5) = 1 1/9 , X != 3/2, 5`
Solve the following quadratic equations by factorization:
`x^2-(sqrt2+1)x+sqrt2=0`
A two digits number is such that the product of the digits is 12. When 36 is added to the number, the digits inter change their places determine the number.
Find the two consecutive positive even integers whose product is 288.
Factorise : m2 + 5m + 6.
Solve the following quadratic equations by factorization: \[\frac{x - 4}{x - 5} + \frac{x - 6}{x - 7} = \frac{10}{3}; x \neq 5, 7\]
Solve the following quadratic equations by factorization: \[\frac{x + 1}{x - 1} + \frac{x - 2}{x + 2} = 4 - \frac{2x + 3}{x - 2}; x \neq 1, - 2, 2\]
Solve the following quadratic equation using formula method only
6x2 + 7x - 10 = 0
Find the roots of the following quadratic equation by the factorisation method:
`3x^2 + 5sqrt(5)x - 10 = 0`
