Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
3x2= x + 4
Advertisements
उत्तर
3x2 = x + 4
⇒ 3x2 – x – 4 = 0
⇒ 3x2 – 4x + 3x – 4 = 0
⇒ x (3x - 4) + 1 (3x - 4) = 0
⇒ (3x - 4) (x + 1) = 0
Either 3x - 4 = 0,
then 3x = 4
⇒ x = `(4)/(3)`
or
x + 1 = 0,
then x = -1
Hence x = `(4)/(3), -1`.
APPEARS IN
संबंधित प्रश्न
Solve for x : `(x+1)/(x-1)+(x-1)/(x+2)=4-(2x+3)/(x-2);x!=1,-2,2`
Find two consecutive positive integers, sum of whose squares is 365.
Solve the following quadratic equations by factorization:
`2/2^2-5/x+2=0`
Solve the following quadratic equations by factorization:
`(x - 3)/(x + 3) - (x + 3)/(x - 3) = 48/7; x ≠ 3, -3`
Determine whether the values given against the quadratic equation are the roots of the equation.
x2 + 4x – 5 = 0 , x = 1, –1
Solve the following quadratic equations by factorization: \[\frac{5 + x}{5 - x} - \frac{5 - x}{5 + x} = 3\frac{3}{4}; x \neq 5, - 5\]
A two digit number is such that the product of its digit is 8. When 18 is subtracted from the number, the digits interchange its place. Find the numbers.
The present age of the mother is square of her daughter's present age. 4 years hence, she will be 4 times as old as her daughter. Find their present ages.
The sum of the squares of three consecutive natural numbers is 110. Determine the numbers.
Solve the following equation by factorization
`(2)/(x^2) - (5)/x + 2 = 0, x ≠ 0`
