Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
x(6x – 1) = 35
Advertisements
उत्तर
x(6x – 1) = 35
⇒ 6x2 - x - 35 = 0
⇒ 6x2 - 15x + 14x - 35 = 0
⇒ 3x (2x - 5) + 7 (2x - 5) = 0
⇒ (2x - 5) (3x + 7) = 0
Either 2x - 5 = 0,
then 2x = 5
⇒ x = `(5)/(2)`
or
3x + 7 = 0,
then 3x = -7
⇒ x = `(-7)/(3)`
Hence x = `(5)/(2), (-7)/(3)`.
APPEARS IN
संबंधित प्रश्न
The time taken by a person to cover 150 km was 2.5 hrs more than the time taken in the return journey. If he returned at a speed of 10 km/hr more than the speed of going, what was the speed per hour in each direction?
`x^2-4x+1=0`
Solve the following quadratic equations by factorization: \[\frac{2}{x + 1} + \frac{3}{2(x - 2)} = \frac{23}{5x}; x \neq 0, - 1, 2\]
Solve the following quadratic equations by factorization:
\[3\left( \frac{3x - 1}{2x + 3} \right) - 2\left( \frac{2x + 3}{3x - 1} \right) = 5; x \neq \frac{1}{3}, - \frac{3}{2}\]
If 2 is a root of the quadratic equation \[3 x^2 + px - 8 = 0\] and the quadratic equation \[4 x^2 - 2px + k = 0\] has equal roots, find the value of k.
If 1 is a root of the quadratic equation \[3 x^2 + ax - 2 = 0\] and the quadratic equation \[a( x^2 + 6x) - b = 0\] has equal roots, find the value of b.
In each of the following determine whether the given values are solutions of the equation or not.
x2 + x + 1 = 0; x = 1, x = -1.
Solve the following equation by factorization
2x2 – 8x – 24 = 0 when x∈I
Solve the following equation by factorization
`(8)/(x + 3) - (3)/(2 - x)` = 2
If x4 – 5x2 + 4 = 0; the values of x are ______.
