Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
6p2+ 11p – 10 = 0
Advertisements
उत्तर
6p2+ 11p – 10 = 0
⇒ 6p2 + 15p – 4p – 10 = 0
⇒ 3p(2p + 5) – 2(2p + 5) = 0
(2p + 5) (3p - 2) = 0
Either 2p + 5 = 0, then 2p = -5 ⇒ p = `(-5)/(2)`
or 3p - 2 = 0, then 3p = 2 ⇒ p = `(2)/(3)`
Hence p = `(-5)/(2), (2)/(3)`.
APPEARS IN
संबंधित प्रश्न
Solve for x :
`1/(x + 1) + 3/(5x + 1) = 5/(x + 4), x != -1, -1/5, -4`
Solve the following quadratic equations by factorization: \[\frac{3}{x + 1} + \frac{4}{x - 1} = \frac{29}{4x - 1}; x \neq 1, - 1, \frac{1}{4}\]
The sum of a number and its reciprocal is `2 9/40`. Find the number.
The difference of the square of two natural numbers is 45. The square of the smaller number is 4 times the larger number. Determine the numbers.
Solve for x:
`(x + 1/x)^2 - (3)/(2)(x - 1/x)-4` = 0.
Solve the following equation by factorization
2x2 – 9x + 10 = 0,when x∈Q
Solve the following equation by factorization
`(x - 3)/(x + 3) + (x + 3)/(x - 3) = 2(1)/(2)`
If the product of two positive consecutive even integers is 288, find the integers.
Solve the following equation by factorisation :
x(x + 1) + (x + 2)(x + 3) = 42
Divide 16 into two parts such that the twice the square of the larger part exceeds the square of the smaller part by 164.
