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Question
Solve the following equation by factorization
3(x – 2)2 = 147
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Solution
3(x – 2)2 = 147
3(x2 - 4x + 4) = 147
⇒ 3x2 - 12x + 12 - 147 = 0
⇒ 3x2 - 12x - 135 = 0
⇒ x2 - 4x - 45 = 0 ...(dividing by 3)
⇒ x2 - 9x + 5x - 45 = 0
⇒ x(x - 9) + 5(x - 9) = 0
⇒ (x - 9) (x + 5) = 0
EIther x - 9 = 0,
then x = 9
or
x + 5 = 0,
then x = -5
Hence x = 9, -5.
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