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Question
Solve the following:
`(2x - 1)/5 = (3x + 1)/3`
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Solution
Given, `(2x - 1)/5 = (3x + 1)/3`
⇒ 3(2x – 1) = 5(3x + 1) ...[By cross-multiplication]
⇒ 6x – 3 = 15x + 5
⇒ 6x – 15x = 3 + 5 ...[Transposing 15x to LHS and – 3 to RHS]
⇒ – 9x = 8
⇒ `(-9x)/(-9) = 8/(-9)` ...[Dividing both sides by – 9]
∴ `x = (-8)/9`
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