Advertisements
Advertisements
प्रश्न
Solve the following:
`(2x - 1)/5 = (3x + 1)/3`
Advertisements
उत्तर
Given, `(2x - 1)/5 = (3x + 1)/3`
⇒ 3(2x – 1) = 5(3x + 1) ...[By cross-multiplication]
⇒ 6x – 3 = 15x + 5
⇒ 6x – 15x = 3 + 5 ...[Transposing 15x to LHS and – 3 to RHS]
⇒ – 9x = 8
⇒ `(-9x)/(-9) = 8/(-9)` ...[Dividing both sides by – 9]
∴ `x = (-8)/9`
APPEARS IN
संबंधित प्रश्न
If you subtract `1/2` from a number and multiply the result by `1/2`, you get `1/8`. What is the number?
The base of an isosceles triangle is `4/3` cm. The perimeter of the triangle is `4 2/15` cm. What is the length of either of the remaining equal sides?
Solve the following equation and check your result:
5x + 9 = 5 + 3x
Solve the following equation and check your result:
8x + 4 = 3(x − 1) + 7
If 6x = 18, then 18x = 54
Solve the following:
`(2x - 3)/(4x + 5) = 1/3`
Solve the following:
0.4(3x – 1) = 0.5x + 1
Solve the following:
4t – 3 – (3t + 1) = 5t – 4
Solve the following:
5(x – 1) – 2(x + 8) = 0
Solve the following:
`3x - (x - 2)/3 = 4 - (x - 1)/4`
